How many grams of copper (II) phopsphate
Favorites|Homepage
Subscriptions | sitemap
HOME > > How many grams of copper (II) phopsphate

How many grams of copper (II) phopsphate

[From: ] [author: ] [Date: 12-03-16] [Hit: ]
00692 x 380.5 = 2.......
how many grams of copper (II) phosphate (molar mass = 380.5) can be made from 35.0 mL of 1.45 M sodium phosphate (molar mass = 164.0) and 25.0 mL of 0.830 M copper (II) chloride (molar mass = 134.5) ??

-
2 Na3PO4 + 3 CuCl2 = Cu3(PO4)2 + 6 NaCl

moles of Na3PO4 = 1.45 Mole Liter ^-1 x .035 L = 0.05075 moles
these can react with 0.05075 x 3 /2 moles of CuCl2 = 0.07613 moles

we actually have .830 x .025 moles of CuCl2 = 0.02075 moles
so the Cu salt is used up first and is the limiting reagent

looking at the equation we see that
the moles of the copper phosphate formed = 0.02075 / 3 = 0.00692 moles

mass formed = 0.00692 x 380.5 = 2.632 g of copper (II) phosphate
1
keywords: II,phopsphate,How,copper,grams,many,of,How many grams of copper (II) phopsphate
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .