Please explain the steps of how you got this
-
You have to provide the quantity of water that is dissolved in the ethylene glycol .
As n example - if you dissolve 1.0kg of water in 10.5kg glycol:
Molar mass H2O = 18g/mol
1000g H2O = 1000/18 = 55.56 mol H2O dissolved in 10.5kg glycol
Molality of water in glycol = moles of water / mass glycol (kg)
Molality = 55.56/10.5
Molality = 5.29m
You can follow method this exactly - only substitute the mass of water actually in your problem.
As n example - if you dissolve 1.0kg of water in 10.5kg glycol:
Molar mass H2O = 18g/mol
1000g H2O = 1000/18 = 55.56 mol H2O dissolved in 10.5kg glycol
Molality of water in glycol = moles of water / mass glycol (kg)
Molality = 55.56/10.5
Molality = 5.29m
You can follow method this exactly - only substitute the mass of water actually in your problem.
-
how many liters of water? you need to give liter of water to find the molarity.
molarity = mole/L
change kg to g. then find the molar mass of C2H6O2. then use molar mass to find the moles.
EDIT:
Density of water is 1.00 g/ml. Use this to find the volume.
molarity = mole/L
change kg to g. then find the molar mass of C2H6O2. then use molar mass to find the moles.
EDIT:
Density of water is 1.00 g/ml. Use this to find the volume.