Help with nmr spectroscopy problem
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Help with nmr spectroscopy problem

[From: ] [author: ] [Date: 13-02-28] [Hit: ]
5 in the opposite carbon of the aromatic group by the ketone,Can someone tell me why two of my hydrogens wouldnt count?-The spectrum of the ethoxybenzaldehyde shows a three hydrogen triplet (the methyl group in the ether) and atwo hydrogen quartet (the methylene group).There are two aromatic signals - H on carbons 2 and 6 and H on carbons 3 and 5.The aldehyde proton is the sharp singlet.p-Nitrotoluene has a similar spectrum:4 aromatic Hs in a pair of doublets and the sharp CH3 singlet.......
i'm having trouble predicting the number of H-NMR signals for
4-ethoxybenzaldehyde
here's the structure: http://static.coleparmer.com/large_image…
I would think that there would be 6 H-nmr signals but there are only 4 when i look it up online. My thinking was that there are 1 and 2 in ethyl by the oxygen, 3 off the 1st carbon of the aromatic group near the oxygen, 4 from the four points in the aromatic ring, 5 in the opposite carbon of the aromatic group by the ketone, and then 6 off the ketone

Can someone tell me why two of my hydrogens wouldn't count?

-
The spectrum of the ethoxybenzaldehyde shows a three hydrogen triplet (the methyl group in the ether) and atwo hydrogen quartet (the methylene group). There are two aromatic signals - H on carbons 2 and 6 and H on carbons 3 and 5. The aldehyde proton is the sharp singlet.

p-Nitrotoluene has a similar spectrum: 4 aromatic H's in a pair of doublets and the sharp CH3 singlet.
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keywords: spectroscopy,problem,Help,with,nmr,Help with nmr spectroscopy problem
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