Calculate the mass in grams of iodine (I2) that will react completely with 61.8 g of aluminum (Al) to form aluminum iodide (AlI3).
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2 Al + 3 I2 → 2 AlI3
(61.8 g Al) / (26.98154 g Al/mol) x (3/2) x (253.809 g I2/mol) = 872 g I2
(61.8 g Al) / (26.98154 g Al/mol) x (3/2) x (253.809 g I2/mol) = 872 g I2