Propane is a gas at room temperature, while candle wax is a solid at room temperature is also part of the question.
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van der waals forces or instantaneous dipole-induced dipole forces exist between molecules of propane and candle wax.
Propane is C3H8 and candle wax is C25H52. van der waals increases as the atoms/molecules get larger due to the increasing number of electrons, therefore larger atoms/molecules will have higher boiling points, c25h52 is a larger molecule than propane, so the van der waals forces in c25h52 will be larger than van der waals in propane and so c25h52 will have a higher boiling point than propane, causing it to be a solid at room temp.
Propane is C3H8 and candle wax is C25H52. van der waals increases as the atoms/molecules get larger due to the increasing number of electrons, therefore larger atoms/molecules will have higher boiling points, c25h52 is a larger molecule than propane, so the van der waals forces in c25h52 will be larger than van der waals in propane and so c25h52 will have a higher boiling point than propane, causing it to be a solid at room temp.
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if i understand your question i think its van der waals interactions
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I dont understand what your asking???