The Ksp of Fe(OH)2 is 4.87×10-17 M3.
Please Help!!
Please Help!!
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Use the pH to calculate pOH and then [OH-]:
pH + pOH = 14.00
pOH = 5.97
[OH-] = 10^-pOH = 1.07 X 10^-6 M
Ksp = [Fe2+][OH-]^2 = 4.87 X 10^-17
[Fe2+] = 4.24X10^-5 M
pH + pOH = 14.00
pOH = 5.97
[OH-] = 10^-pOH = 1.07 X 10^-6 M
Ksp = [Fe2+][OH-]^2 = 4.87 X 10^-17
[Fe2+] = 4.24X10^-5 M