the H+ and OH- bind in a 1:1 ratio.
therefore, the moles of H+ used will be the moles of OH- neutralized
0.025L x 0.1M = 0.0025moles H+
0.04L x M = 0.0025moles OH-
M NaOH = 0.062M
therefore, the moles of H+ used will be the moles of OH- neutralized
0.025L x 0.1M = 0.0025moles H+
0.04L x M = 0.0025moles OH-
M NaOH = 0.062M