Chemistry help. need to figure out freezing point of solution

Some physical properties of water are shown below.

freezing point 0.00°C
boiling point 100.00°C
Kf 1.86°C/m
Kb 0.512°C/m
What is the freezing point of a solution of calcium chloride that contains 73.0 g CaCl2 dissolved in 333 g of water?

*part two of the question asked me to figure out the boiling point which i can do i just am struggling with the freezing point

cacl2 has 1.975 mols. i know i multiple this by Kf which would then be 3.67 but i don't know where to go from here.

thanks for the help!

Kf=iKfm
Solute=CaCl2
Solvent=H2O
i=3 (solute)
Kf=1.86 (solvent)
m=0.65mol/0.333kg=1.95m
=(3)(1.86)(1.95)=10.88
NFP=0.00-10.88=-10.88 deg. Celsius is the new freezing point