Biology (Genetics) Study guide, Not sure what question is asking..

In any given genotype, only those alleles that are heterozygous will have more than one possible gamete formed.

TTRR, TTrr, ttRR, and ttrr are all homozygous for both alleles. So there will be only one possible gamete: TR, Tr, tR, tr.

For the remainder of the above genotypes, look for the number of heterozygous pairs of alleles.
TTRr: TR or Tr
TtRR: TR or tR
TtRr: TR, Tr, tR, tr
ttRr: tR or tr

You are simply being asked to show all gametes in terms of probability - the question is designed to show that you understand that each allele is inherited independently.

TTRR. Pr (T allele) = 1, Pr (R allele) = 1, so Pr(TR gamete) = 1 x 1= 1. i.e. all gametes will be TR.

TTRr. Pr (T allele) = 1, Pr (R allele) = 0.5, Pr (r allele) = 0.5, so Pr (TR gamete) = 1 x 0.5 = 0.5

If that is too formal for you then express it in language that is more familiar.

So for example for TtRr - 1/2 the gametes will contain T, the other half t. Likewise 1/2 will contain R the other half r. So TR = 1/2 x/1/2 = 1/4, Tr, tR and tr all the same. No more than that.