Biology (Genetics) Study guide, Not sure what question is asking..

Using Principles of Probability, show the types of gametes that are possible from individuals with the following genotypes: TTRR, TTRr, TTrr, TtRR, TtRr, Ttrr, ttRR, ttRr, and ttrr.

Could anyone help me please?

This all sounds very confusing without a visual aid but i will try my best. These genotypes are involving two characteristics. A gamete is the sex cell produced from an organism with reference to these genotypes. If they are not linked -for each genotype - you take the first the T's and pair it with the first of the R's, then take the first T and match it with the second R, the the second T and the first R, and the second T and the second R - like doing a dihybrid cross. For example - TtRr splits to make a TR gamete, a Tr gamete, a tR gamete and a fourth tr gamete. However not all of the genotypes will produce 4 gametes. For example TTRR will only produce a TR gamete. I hope this has made sense.

In Mendelian inheritance, traits are independently assorted, and have the same probability as throwing a coin, it either lands head up or head down.
The genotypes shown have two traits, T and R. The traits are either dominant, characterized by a capital T or R, or recessive, characterized by a small letter.
Since they get separated during meiosis, the gametes only end up with one of the alleles, that means, only one of the T and one of the R.
For the first example, you have TTRR, there is only one possibility for the gametes: TR.
The second example is still homozygous on the T, but heterozygous on the R. You have two possibilities: TR or Tr.
When you ahve two heterozygous traits, TtRr, you use the FOIL method and your results will be: TR, Tr, tR, tr.
You always have as many probabilities and possibilities as there are number of alleles of one trait multiplied with the number of alleles of the next trait. Example:
TTRR has 1 trait for T and one for R. 1 x 1 = 1.