Is this answer correct PHYSICS

A cup is made of an experimental material that can hold hot liquids without significantly increasing its own temperature. The 0.75 kg cup has an initial temperature of 36.5 °C when it is submerged in 1.25 kg of water with an initial temperature of 20.0 °C. What is the cup's specific heat capacity if the final temperature is 24.4 °C?

1) I used the formula: (m1)(Cp1)(ΔT2)=(m2)(Cp2)(ΔT2)
2) Substituted with actual values: (.75kg)(Cp)(36.5-24.4)=(1.25kg)(4186J/kg…
3) Multiplied each side: 9.075Cp=2302300
4) Divided each side by 9.075Cp: 2302300/9.075Cp
5) My final answer is: Cp=253697 J/kgC

Please check my answer because i honestly don't know if i'm doing this correctly. Thank You.

Let us check with general method

Heat gained by water = heat lost by cup
m1c1ΔT1 = m2c2ΔT2
c2 = m1c1ΔT1/m2ΔT2 = (1.25*4186*4.4)/0.75*12.1 = 23023/9.075 = 2536.97 J/kg K

Hence c2 = 2536.97 J/kg K

So, what your mistake is 1.25*4186 = 23023 but not 2302300:)