Four blocks EACH of mass m = 10.0 kg are arranged as shown in the picture, on top of a frictionless table. A hand touching block 1 applies a force of Fh1 = 90.0 N to the right. The coefficient of friction between the blocks is sufficient to keep the blocks from moving with respect to each other.
What is the total force exerted by block 2 on block 3 ?
here is the diagram
http://i49.tinypic.com/68woyq.gif
What is the total force exerted by block 2 on block 3 ?
here is the diagram
http://i49.tinypic.com/68woyq.gif
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I think block 2 would exert a force to block 3 equal to the combined weight of the 2 books above it.
Fn = 2(mg) = 2*10*9.8 = 196 N
could be wrong
Fn = 2(mg) = 2*10*9.8 = 196 N
could be wrong