In a double-slit experiment, if the slit separation is increased, which of the following happens to th

In a double-slit experiment, if the slit separation is increased, which of the following happens to the interference pattern shown on the screen?


a.The maxima stay at the same position.
b. The minima and maxima stay at the same position.
c. The minima stay at the same position.
d. The maxima get further apart.
e. The minima get closer together.

I think the maxima stays at the same position, I'm not sure though.

w = ((lamda)D)/s, where D is constant here, as is lambda. So we're left with:
w is inversely proportional to 1/s. Mathematically, if s, the slit separation increases, then 1/s becomes much less and therefore w decreases. W is the distance betrween each fringe. If this decreases, the maxima get closer together, which is an answer I think you've missed.