How do I find the values of a and b: 3ax + 6 -4(x+ b) ≡ 11x + 14?

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answers:
Ash say: 3ax + 6 -4(x+ b) ≡ 11x + 14
3ax + 6 - 4x - 4b ≡ 11x + 14
(3a - 4)x + (6 -4b) ≡ 11x + 14
As you see, the x coefficients should be same, while the constants should be same
3a-4 = 11
3a = 15
a = 5
Also
6-4b = 14
-4b = 8
b = -2

a = 5 and b = -2
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Como say: (3a - 4) x - 4b = 11x + 8

3a - 4 = 11
- 4b = 8

3a = 15
4b = - 8

a = 5 , b = - 2
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gpqfr say: lhlprfrx
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