Lim x->1 [sin(lnx)] /[ (x^2)-1]?

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answers:
khalil say: x → 1 then 0/0
hopital rule .. der top / der bottom

[cos(lnx) 1/x] / 2x =

cos(lnx) / 2x² = 1/2 when x → 1
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lxjph say: pfhvbrnz
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dbrlt say: uxpvvunv
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