Absolute Value Inequality?
Solve |2x-1|+5>2
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answers:
Captain Matticus, LandPiratesInc say: |2x - 1| > -3

|t| is greater than or equal to 0 for all values of t, so we're already set. This is true for all values of 2x - 1, and thus true for all values of x
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la console say: |2x - 1| + 5 > 2 → you subtract 5 both sides

|2x - 1| + 5 - 5 > 2 - 5 → you simplify

|2x - 1| > - 3 ← an absolute value is always a positive value (or null)

In this present case, as an absolute value is always ≥ 0, so you can say that this absolute value is always > - 3 whatever the value of x.

Solution = IR
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MyRank say: |2x-1|+5 > 2

2x-1+5 > 2

2x + 4 > 2

2x + 2 > 0

2x > -2

x > -1

(or)

-2x + 1 + 5 > 2

-2x + 6 > 2

-2x + 4 > 0

2x - 4 < 0

2x < 4

x < 2.
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khalil say: |2x-1|+5>2

x = 1/2 → 5 >2
x > 1/2 → always 2x -1 +5 >2
x < 1/2 → always 1-2x +5 > 2
so
-∞< x < +∞
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say: |2 x-1|+5>2
True
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Krishnamurthy say: |2x - 1| + 5 > 2
True
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