What is the equation of the line for coordinates y (0,3) and x (2,0), with steps?

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answers:
MyRank say: y (0, 3), x (2, 0)

Equation of line

y - y₁ = y₂-y₁/(x₂-x₁) (x-x₁)

(y - 3) = 0 - 3/ 2 - 0 (x - 0)

(y - 3) = -3/2 (x)

2y - 6 = -3x

3x + 2y - 6 = 0

Required equation 2y = -3x + 6

y = (-3/2)x + 3.
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David say: Points: (0, 3) and (2, 0)
Slope: -3/2
Equation: y = -3/2x +3
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Como say: Points are (0,3) and (2,0)
Gradient , m = - 3/2
y - 3 = (-3/2) x
y = (-3/2) x + 3
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lenpol7 say: y - 3 = [(3- 0) / (0 -2)]( x - 0 )
y - 3 = [ 3/-2](x)
y = (-3/2)x + 3
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sepia say: (2, 0) and (0, 3)
Gradient of line = (change in y)/(change in x) = 3/-2
Equation of a line = y - y1 = m (x - x1) = y - 0 = -3/2(x - 2)
y = -3/2x + 3
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electron1 say: Let’s determine the x and y coordinates of the two points.
#1 (2, 0)
#2 (0, 3)

The following equation shows the relationship between the x and y components of the point on a line.

y = m * x + b

m is the slope of the line. We can use the following equation to determine the slope of this line.

Slope = (y2 – y1) ÷ (x2 – x)
Slope = (3 – 0) ÷ (0 – 2) = -3/2

b is the y intercept. This is the point where the line crosses the axis. The x component of this point is 0. So, the intercept is 3.

y = -3/2 * x + 3

To prove that his is true, let’s use coordinates of the first point.

0 = -3/2 * 2 + 3 = 0
I hope this is helpful for you.
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Brendan Berney say: First find the slope by dividing the difference is y coordinates by the difference in x coordinates. (3-0)/(0-2)=-3/2. Be consistent in which coordinates you subtract from.

Then use that slope and either set of coordinates and plug it into point slope form equation y-y1=m(x-x1) where x1 and y1 are your coordinates and m is your slope. You can distribute and turn it into y=mx+b form:
y-3=-3/2(x-0)
y-3=-3/2x
y=-3/2x+3

Check your answer by plugging either pair of coordinates into your equation:
y=-3/2x+3
3=-3/2(0)+3
3=3
y=-3/2x+3
0=-3/2(2)+3
0=-3+3
0=0
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