What is the equation of the line that intercepts the y axis at (0,3) and the x axis at (2,0)?
I do not understand how they got
y = (-3\2)x + 3. When I do it I say
, 3 = -3\2 (2) + b.
I get 0 as b.
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answers:
Philomel say: The equation of the line is: y= mx+B
3x+2y=6
2y=-3x+6
y= - 1.5x+3
KhanAcademy.org >>review the videos on Equation of a line.
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Priyankka say: Equation of a line through 2 points is:
(y-y1)/(y2-y1) =(x-x1)/(x2-x1)
Here, (x1,y1)=(0,3) and (x2,y2)=(2,0)

(y-3)/(0-3) = (x-0)/(2-0)
Solving this we get,
3x+2y-6=0
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G. say: Steps

1. Find the slope m.

2. Use the point-slope formula
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Como say: m = ( 0 - 3 ) / ( 2 - 0 ) = - 3/2
y - 3 = (-3/2) ( x - 0 )
y = (-3/2) x + 3
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Ian H say: y = mx + c, substitute the given values for y and x,
3 = 0*x + c
y = mx + 3
0 = 2m + 3
y = -(3/2)x + 3
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David say: Points: (0, 3) and (2, 0)
Slope: -3/2
Equation: y = (-3/2)x +3
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