Can anyone answer this for me?
I'm totally stuck and want to see if I can see what the right answer is so I can try and work backwards. Let the 2x2 matrix R represent a rotation that rotates a 2D object counter-clockwise 70 degrees around the coordinate origin. Suppose R = ( r 11 r 12 r 21 r 22 ) Find the value for element r12....
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answers:
Vaman say: Let old coordinates be x1 and x2. The new coordinates be y1 and y2l In the rotation, you can write in matrix form
|x1| = |y1 cos a+y2 sin a|
|x2} = |y1 sin a+ y2 cos a|
If you compare you get r11= cos a= cos 70=0.34=r22,, r12=0.93=21
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tdndt say: clygktpd
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Michael E say: the generalized 2 dimensional Jacobian matrix is

Cos(x), Sin(x)
-Sin(x), Cos(x)
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say: Yes. Someone can.
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wpgba say: jxkpvjgs
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hfhpl say: wjllynue
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glrlf say: ppdvrhzf
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mhrxa say: tuemhccw
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