A rectangular parking lot that is 3 feet longer than it is wide has an area of 550 how long is the parking lot

thank you for your time.

x(x+3) = 550
x^2 + 3x - 550 = 0
(x-22)(x+25) = 0
x = 22; x = -25
Of course, you can't have a negative width, so x = 22.

Width: 22 ft.
Length: 25 ft

L=3+w
WL=550

w(3+w)=550
w^2+3w-550

(w+25)(w-22)=0
w=-25 or w=22
since area cannot be negative the answer is 22 ft

Let Width = x ft
then length = x+3 ft
Area = x(x+3) ft²
→x(x+3)=550
or x²+3x−550=0
(x+25)(x−22) =0
Now either (x+25) = 0 i.e x=−25 or (x−22) =0 i.e x= 22
Since x is positive hence x= 22 ft
Width = 22 ft
and length = 22+3=25 ft

x is the width x+3 is the length

x(x+ 3)=550 x^2+3x=550 x^2+3x-550=0

factor (x+ 25)(x-22) x cannot be negative therefore x-22=0 x=22 that is the width

now add 3 to 22 and you get the length

x * y = 550

but y = x + 3

x(x + 3) = 550
x^2 + 3x - 550 = 0
(x + 25)(x - 22) = 0

x = -25, 22
since x > 0,
x = 22, so the other side has to be 25.

Hi,

x(x - 3) = 550

x² - 3x - 550 = 0

(x - 25)(x + 22) = 0

x = 25 or x = -22 <=discard

length: 25 feet <==ANSWER

I hope that helps!! :-)