3.)
Find the derivative of the function:
f(x) = sqrt(x) - 2cbrt(x)
sqrt means square root and cbrt means cube root
5.)
Find the second differentiation of the function:
y^3 = x^4
Please show all work and 10 points to most accurate answer! Thanks for all answers in advance!
Find the derivative of the function:
f(x) = sqrt(x) - 2cbrt(x)
sqrt means square root and cbrt means cube root
5.)
Find the second differentiation of the function:
y^3 = x^4
Please show all work and 10 points to most accurate answer! Thanks for all answers in advance!
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3) think of the problem this way: f(x) = (x)^1/2 - 2*(x)^1/3
Now the derivative becomes obvious: df(x)/dx = 1/2(x)^-1/2 - 2*(1/3)*(x)^-2/3
5) In this case, I think there is something missing from the question, because you have two variables, y and x.
If what you are asking is "what is the second partial derivative with respect to x?" Then the answer would be:
dy/dx = 0 = 4x^3
d2y/dx2 = 0 = 12x^2
Thinkingblade
Now the derivative becomes obvious: df(x)/dx = 1/2(x)^-1/2 - 2*(1/3)*(x)^-2/3
5) In this case, I think there is something missing from the question, because you have two variables, y and x.
If what you are asking is "what is the second partial derivative with respect to x?" Then the answer would be:
dy/dx = 0 = 4x^3
d2y/dx2 = 0 = 12x^2
Thinkingblade
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sqrt means SQUIRT and make babies with women