Calculus 1 Questions on Derivatives? Questions #3 and #5
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Calculus 1 Questions on Derivatives? Questions #3 and #5

[From: ] [author: ] [Date: 12-06-02] [Hit: ]
Thanks for all answers in advance!5) In this case, I think there is something missing from the question, because you have two variables, y and x.If what you are asking is what is the second partial derivative with respect to x?......
3.)
Find the derivative of the function:
f(x) = sqrt(x) - 2cbrt(x)
sqrt means square root and cbrt means cube root

5.)
Find the second differentiation of the function:
y^3 = x^4

Please show all work and 10 points to most accurate answer! Thanks for all answers in advance!

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3) think of the problem this way: f(x) = (x)^1/2 - 2*(x)^1/3

Now the derivative becomes obvious: df(x)/dx = 1/2(x)^-1/2 - 2*(1/3)*(x)^-2/3

5) In this case, I think there is something missing from the question, because you have two variables, y and x.

If what you are asking is "what is the second partial derivative with respect to x?" Then the answer would be:

dy/dx = 0 = 4x^3
d2y/dx2 = 0 = 12x^2

Thinkingblade

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sqrt means SQUIRT and make babies with women
1
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