b^3-3b^2-54b
please factor.
thanks so much!
please factor.
thanks so much!
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Because every term has a b you can factor out the gcf of b
b(b²-3b-54)
Now factor the quadratic
b(b-9)(b+6) <---- Answer
b(b²-3b-54)
Now factor the quadratic
b(b-9)(b+6) <---- Answer
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b^3 - 3b^2 - 54b
You can factor b out of this trinomial.
b(b^2 - 3b - 54)
Then, factor what is in the parentheses.
b(b+6)(b-9)
Hope this helps!
You can factor b out of this trinomial.
b(b^2 - 3b - 54)
Then, factor what is in the parentheses.
b(b+6)(b-9)
Hope this helps!
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You need to find two numbers whose product is -54 and whose sum is -3. Those two numbers are -9 and 6
b(b - 9)(b + 6)
b(b - 9)(b + 6)
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b^3-3b^2-54b = b(b-9)(b+6)