Ok please help me do this :
The binary operation * is defined by a * b = (a + b)^2 - 2ab
Calculate thte value of ( 3 * 4 ) * 2
i tried it but i don't think i am right so i am getting really confused with this sum. PLEASE HELP ME
The binary operation * is defined by a * b = (a + b)^2 - 2ab
Calculate thte value of ( 3 * 4 ) * 2
i tried it but i don't think i am right so i am getting really confused with this sum. PLEASE HELP ME
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3+4 = 7
7^2 = 49
49- (2 x 3 x 4 ) = 25
25 +2 = 27
27^2 = 729
729- (2 x 25 x 2) =629
ANSWER = 629
7^2 = 49
49- (2 x 3 x 4 ) = 25
25 +2 = 27
27^2 = 729
729- (2 x 25 x 2) =629
ANSWER = 629
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first calculate 3*4 = (3+4)^2 - 2*3*4 = 25(the asterisk on right hand sign is multiplication sign and not the binary operator)
now it becomes 25*2 = (25+2)^2 - 2*25*2 = 629 (again the asterisk on right hand side is multiplication sign and not the binary operator)
now it becomes 25*2 = (25+2)^2 - 2*25*2 = 629 (again the asterisk on right hand side is multiplication sign and not the binary operator)