Convert the product into Factorial

(n+1)(n+2)(n+3)...........(2n)

answer = (2n)! / n!
I need to know the steps involved

(2n)! = (1) (2) (3) ∙∙∙ (n) (n + 1) (n + 2) (n + 3) ∙∙∙ (2n - 1) (2n)

Dividing (2n)! by n!, you have
[(1) (2) (3) ∙∙∙ (n) (n + 1) (n + 2) (n + 3) ∙∙∙ (2n - 1) (2n)]
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[(1) (2) (3) ∙∙∙ (n)]

This removes the first n factors from (2n)!, leaving you with the desired
(n + 1) (n + 2) (n + 3) ∙∙∙ (2n - 1) (2n)

1x2x3x4x...xnx(n+1)(n+2)...(2n)=2n!
but we start our product from(n+1) so n! is out...
answer 2n!/n!