I seem to be getting the wrong answer.
Answer is 123*C
5.25g of Krypton
2.75L vessel
75 kPa
give in Celsius
(5.5g)(1mole) / (83.798g) = 0.0656 moles
(75kpa)(1atm) / (101.3kPa) = 0.74 atm
PV/RN = T (K)
(0.74atm)(2.75L) / (0.08206)(0.0656mol)
T= 378.44 K
T= 105.29*C
I also tried it with the 8.314 R constant with kPa as pressure; got the same number
Could the text book be wrong?
Answer is 123*C
5.25g of Krypton
2.75L vessel
75 kPa
give in Celsius
(5.5g)(1mole) / (83.798g) = 0.0656 moles
(75kpa)(1atm) / (101.3kPa) = 0.74 atm
PV/RN = T (K)
(0.74atm)(2.75L) / (0.08206)(0.0656mol)
T= 378.44 K
T= 105.29*C
I also tried it with the 8.314 R constant with kPa as pressure; got the same number
Could the text book be wrong?
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You're are right in your process, but you made a mistake with the grams of Krypton. In your equation you have 5.5g and it should be 5.25g/83.80 g/mol = 0.0626 moles Krypton
so putting the correct number in your furhter equations will give you
0.74atm x 2.75L = 0.08206L*atm/mol K x 0.0626mol x T
T = 2.035 / 0.00514
T = 395.91 K
T = 122.76 C of course you must consider significant figures, so it rounds to 123 C
so putting the correct number in your furhter equations will give you
0.74atm x 2.75L = 0.08206L*atm/mol K x 0.0626mol x T
T = 2.035 / 0.00514
T = 395.91 K
T = 122.76 C of course you must consider significant figures, so it rounds to 123 C