I believe the answer is 18.78% please double check for me!
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Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol = 2 mol Li = 6.94*2 = 13.88g
% Li = 13.88/73.89*100 = 18.78% perfectly correct.
Molar mass Li = 6.94g/mol = 2 mol Li = 6.94*2 = 13.88g
% Li = 13.88/73.89*100 = 18.78% perfectly correct.