Oxidation is the loss of electrons
Reduction is the gain of electrons
what is the relation between gain of oxygen and loss of electrons?
Reduction is the gain of electrons
what is the relation between gain of oxygen and loss of electrons?
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oxidation------1.increase in non metal [2 FeCl2+ Cl2 ----->2 FeCl3 ]
2. decrease in metal [ Cu2Cl2 + Cl2--------> 2 CuCl2 ]
3.increase in oxidation number
4. gain of oxygen
5. loss of hydrogen
6. loss or removal of electrons
and the vice -versa is reduction
[ by gaining oxygen or by losing electrons there is an increase in OXIDATION NUMBER.
e.g. 2 Ca + O2------------> 2CaO [ O.N. of Ca is increased from zero to +2]
Ca - 2e- ------------------> Ca++ [ O.N.of Ca is increased from zero to +2 ]
2. decrease in metal [ Cu2Cl2 + Cl2--------> 2 CuCl2 ]
3.increase in oxidation number
4. gain of oxygen
5. loss of hydrogen
6. loss or removal of electrons
and the vice -versa is reduction
[ by gaining oxygen or by losing electrons there is an increase in OXIDATION NUMBER.
e.g. 2 Ca + O2------------> 2CaO [ O.N. of Ca is increased from zero to +2]
Ca - 2e- ------------------> Ca++ [ O.N.of Ca is increased from zero to +2 ]
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While the word "oxidation" has "oxygen" as its root, the relationship between oxidation and oxygen is now merely historical. Your statement about the loss and gain of electrons is what now defines the processes and, if oxygen is involved, it is merely coincidental. For example:
Na(s) ---> Na+ + e-
(half reaction for oxidation of sodium metal, no oxygen involved)
Cl2 + 2e- ---> 2Cl-
(half reaction for reduction of chlorine gas, no oxygen involved)
Combining these 2 half reactions and balancing gives:
2Na + Cl2 ---> 2NaCl
(and there still is no oxygen involved)
Historically, "oxidation" got its name because the burning of substances in air were the easiest, most readily available things to study and it quickly became apparent that it was the O2 in the air that was responsible for the burning process. Also, because oxygen's high electron affinity, oxidation became associated with the transfer of electrons to oxygen, ie, a substance was said to be oxidized when it gave up electrons to oxygen.
Nonetheless, that is all historical and the modern definition of oxidation, as you stated in your question, has nothing specifically to do with oxygen.
Na(s) ---> Na+ + e-
(half reaction for oxidation of sodium metal, no oxygen involved)
Cl2 + 2e- ---> 2Cl-
(half reaction for reduction of chlorine gas, no oxygen involved)
Combining these 2 half reactions and balancing gives:
2Na + Cl2 ---> 2NaCl
(and there still is no oxygen involved)
Historically, "oxidation" got its name because the burning of substances in air were the easiest, most readily available things to study and it quickly became apparent that it was the O2 in the air that was responsible for the burning process. Also, because oxygen's high electron affinity, oxidation became associated with the transfer of electrons to oxygen, ie, a substance was said to be oxidized when it gave up electrons to oxygen.
Nonetheless, that is all historical and the modern definition of oxidation, as you stated in your question, has nothing specifically to do with oxygen.
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Yes , they have something to do with you. The charge you win or lose is the product of the electron you win or lose and the charge e (which is negative) . this means then that you lose one electron you increase your charge with +e and if you win 2 electrons you decrease your charge by -2e
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i dont know