calculate the number of grams in 1.693 x 10^24 atoms of MgCo3
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Molecular wt of MgCO3 =24+12+48=84 g
No of atoms= 1.693*10^24
No of moles= No of atoms/(6.022*10^23)=2.81
Again,
No of moles= Mass in gram/Molecular wt of MgCO3
Mass in gram=No of gram=236.15 g
No of atoms= 1.693*10^24
No of moles= No of atoms/(6.022*10^23)=2.81
Again,
No of moles= Mass in gram/Molecular wt of MgCO3
Mass in gram=No of gram=236.15 g