Chemistry Homework - Please Help If You Can
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Chemistry Homework - Please Help If You Can

[From: ] [author: ] [Date: 12-06-01] [Hit: ]
543M of H2SO4 contains 0.543*0.072=0.as you need 2 moles of KOH to neutralize 1mole of H2SO4 you need 0.0391*2=0.which are in 39.......
If 72.1 ml of 0.543 M H2SO4 is needed to neutralized 39.0 ml of KOH solution, what is the molarity of the KOH solution? Show the balanced equation.

Thank you (will choose best answer)

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2KOH+H2SO4--> K2SO4 +2H2O
you see , you need 2 molecules of KOh to neutralize 1 mole of H2SO4

we calculate the number of moles of H2SO4 in 72.1mL=0.072L
1liter of 0.543M of H2SO4 contains 0.543*0.072=0.0391moles of H2SO4

as you need 2 moles of KOH to neutralize 1mole of H2SO4 you need 0.0391*2=0.0782moles of KOH
which are in 39.0 mL = 0.039L

So the molarity of your solution is 0.0782/0.039=2.004M or 2M rounded
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