Carbon reacts with steam, H2O, to produce hydrogen and carbon monoxide according to the following reaction...

C + H2O -> H2 +CO

a. If 2.40 mol of carbon are exposed to 3.10 mol of steam, which is the limiting reagent?

b. How many moles of each product are formed?

c. What mass of each product is formed?

Thanks for answering in advance! I know it's a lot but I appreciate it!

Look at the balanced equation, which you have given: C + H2O → H2 + CO
It shows that one mole of carbon will react with one mole of oxygen, so for
(a) - We have 2.4 moles of C and 3.1 moles of H2O, so we have extra steam.
The limiting reagent is the carbon; when it is used up we have 0.7 mole H2O
(b) - If we begin with 2.4 moles of C and extra water, we can only form 2.4
moles of each product, so we get 2.4 moles of CO and 2.4 moles of H2.
(c) - The molecular weight of CO is 28, so we get 2.4 * 28, or 67.2 gm. of CO
The molecular weight of H2 is 2, so we produce 4.8 grams of H2 gas.
Hope this answers all your question!