a. Write the balanced equation for the reaction.
b. How much sulfur dioxide in grams is formed when 2.0 x 104 kg of coal that is 0.05% by mass pyrite is burned?
b. How much sulfur dioxide in grams is formed when 2.0 x 104 kg of coal that is 0.05% by mass pyrite is burned?
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4FeS2+11O2->8SO2+2Fe2O3
SO2+C->S+CO2
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m(FeS2)=2*10^4*5*10^(-4)=10 kg
n(FeS2)=10:120=0,083 kmol=83 mol
n(SO2)=166 mol
m(SO2)=166*64=10624 g
SO2+C->S+CO2
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m(FeS2)=2*10^4*5*10^(-4)=10 kg
n(FeS2)=10:120=0,083 kmol=83 mol
n(SO2)=166 mol
m(SO2)=166*64=10624 g