Sand poured on the ground forms a conical pile whose altitude is always one half the radius of the base. When the height of the pile is 40 in. it's increasing at 3 in/min. How fast is the sand falling?
(Use v=1/3pi(r^2)h
(Use v=1/3pi(r^2)h
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r = 2h ---> V = (4/3)pi h^3 ---> dV/dt = 4pi h^2 dh/dt , plug values and sove dV/dt
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19,200pi in/min should be the answer then right?
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