Reduce relationship to linear law

y = k (x + 1 ) ^ n

Using log/In

Thank you!

y = k (x + 1 ) ^ n

log(y) = log[k(x+1)^n] = log(k) + log[(x+1)^n] = log(k) + n*log(x+1)

which has the form of the linear equation:

a = b + n*c

where
a = log(y)
b = log(k)
c = log(x+1)